Maximize p = x + y subject to...?!
Question: Maximize p = x + y subject to...?
x + 4y <= 5
4x + y <= 5
x >= 0
y >= 0
p=?
x=?
y=?
4x + y <= 5
x >= 0
y >= 0
p=?
x=?
y=?
Answers:
Add and subtract both the equations you will get
x+y=2 and x-y=0;
x=y=1 and p=2