Probability Statistics Question?!
Question: Probability Statistics Question!?
Researchers have for a long time been interested in the relationship between cigarette smoking and lung cancer!. The following table shows percetntages of adult females observed in a recent study!.
Smokes Does not smoke
Gets Cancer 0!.06 0!.03
Does not get Cancer 0!.15 0!.76
Suppose an adult female is randomly selected from this particular population what is the prob of the following
She smokes and gets cancer
she doesnt get cancer
she doesn not smoke or does not get cancer
she gets cancer if she smokes
she does not get ancer knowing she does not smoke
HELP WTF!?
0!.06Www@Answer-Health@Com
Smokes Does not smoke
Gets Cancer 0!.06 0!.03
Does not get Cancer 0!.15 0!.76
Suppose an adult female is randomly selected from this particular population what is the prob of the following
She smokes and gets cancer
she doesnt get cancer
she doesn not smoke or does not get cancer
she gets cancer if she smokes
she does not get ancer knowing she does not smoke
HELP WTF!?
0!.06Www@Answer-Health@Com
Answers:
It's all a matter of interpreting what the question is asking and some simple probability calculations!.
1) The probability of her smoking and getting cancer is 0!.06 or 6%
2) Her probability of not getting cancer as a member of the population is 0!.15+0!.76=0!.91 or 91%
3) The probability of her not smoking and not getting cancer is simply 0!.76, or 76%
4) If she smokes, her probability of getting cancer is 0!.06/(0!.06+0!.15)=0!.286 or 28!.6%
5) If she doesn't smoke, the the probability of not getting cancer is 0!.76/(0!.03+0!.76)=0!.962 or 96!.2%Www@Answer-Health@Com
1) The probability of her smoking and getting cancer is 0!.06 or 6%
2) Her probability of not getting cancer as a member of the population is 0!.15+0!.76=0!.91 or 91%
3) The probability of her not smoking and not getting cancer is simply 0!.76, or 76%
4) If she smokes, her probability of getting cancer is 0!.06/(0!.06+0!.15)=0!.286 or 28!.6%
5) If she doesn't smoke, the the probability of not getting cancer is 0!.76/(0!.03+0!.76)=0!.962 or 96!.2%Www@Answer-Health@Com
U should post this question in SCIENCE AND MATH column
Anyway
a) smoke and get cancer
P = 0!.06
b) smoke and doesn't get cancer
P = 0!.03
c) doesn't smoke or doesn't get cancer
P = P that the girl picked is non smoker + P doesn't get cancer
This question cannot be solve unless u give me the population of the respondents!. (how many girls involved in this research) Saying that the girl is randomly picked is not helpful without saying the populationWww@Answer-Health@Com
Anyway
a) smoke and get cancer
P = 0!.06
b) smoke and doesn't get cancer
P = 0!.03
c) doesn't smoke or doesn't get cancer
P = P that the girl picked is non smoker + P doesn't get cancer
This question cannot be solve unless u give me the population of the respondents!. (how many girls involved in this research) Saying that the girl is randomly picked is not helpful without saying the populationWww@Answer-Health@Com