When two parents are carriers of the sickle cell anemia??!


Question: When two parents are carriers of the sickle cell anemia!?!?
Hi
This is some homework help!!!
The question is = You are a genetic councelor and a couples test results reveal that they are both carriers of sickle cell anemia!. What can you tell them about their chances of any child of theirs exhibiting this disease!?!?!?!?
Hope you guys can help =)Www@Answer-Health@Com


Answers:
They're both carrying the recessive gene that can cause sickle cell anemia!. In order for any of their children to contract the disease, the child will need to inherit the recessive gene from both parents!. If the child only inherits the recessive from one parent, then sickle cell anemia will not result!.

Each of their offspring would have a 25% chance of having sickle cell anemia!.Www@Answer-Health@Com

Using a punnnett square will tell you the answer!. You should show the square with your work!. That's what I require of my students!. Now if both are carriers, their genotypes are both Ss!. When you cross 2 heterozygous parents, you always get a 25% chance of homozygous dominant (not a carrier or affected by the disease), 50% heterozygous (a carrier, but not exhibiting the disease), and 25% homozygous recessive (exhibiting the disease)!. This is because sickle cell anemia is a recessive disorder!. It is important to remember that these percentages are the chances with every pregnancy, not a percentage of the offspring with each genotype!.Www@Answer-Health@Com

Since they both are heterozygous for sickle cell anemia their children each have a 25% chance of being homozygous for Sickle Cell and have Sickle Cell Anemia, a 50% chance of being heterozygous for Sickle Cell like themselves, and a 25% chance of being homozygous for Normal and having no Sickle Cell genes!.Www@Answer-Health@Com

They have a 25% chance!. If you do a punnet square(I assume you know what that is), you will see that only one out of 4 squares ends up being homozygous recessive for sickle cell anemia!. 50% chane of children being carriers, and 25% chance of the child not having the gene!.Www@Answer-Health@Com

Sickle cell anemia is a recessive trait!. If both parents are carriers, they have a 1:4 or 25% chance of having a child with the disease!. There is a 2:4 (1:2) or 50% chance that their child will be a carrier and a 25% chance the child will be completely "normal!."Www@Answer-Health@Com

http://www!.sicklecellsociety!.orgWww@Answer-Health@Com





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